Mathigo
Grades 2–3

Add with a Compensation Strategy

Add the next ten, then give back the extra 1 you put in.

19, 29, and 39 are awkward because they sit one below a ten. Adding the ten is easy: 27 + 20 lands on a number you can see. You put in 1 too many, so you give that 1 back at the end. The total does not change if the extra goes in and then comes back out.

27 + 19. 19 is 1 less than 20. First add the 20: 27 + 20 = 47. Then take the extra 1 away: 47 − 1 = 46. So 27 + 19 = 46.

  1. See how close the second number is to the next ten.
  2. Add that ten instead.
  3. Subtract the extra you put in.
  4. The amount you subtract is the same amount you added on.

36 + 29 uses the same move. 29 is 1 less than 30. 36 + 30 = 66, then 66 − 1 = 65. 48 + 19: 48 + 20 = 68, then 68 − 1 = 67.

Watch out

  • Adding the 1 at the end instead of subtracting it. You already put that 1 in.
  • Changing only one addend and leaving the total unfixed.
  • Subtracting 10 when you only borrowed 1 to reach the ten.

What is 36 + 29?

36 + 30 = 66, then 66 − 1 = 65, because 29 is 1 less than 30.

What if the number is 2 below the ten, like 28?

Add the ten, then subtract 2. 35 + 28 is 35 + 30 = 65, then 65 − 2 = 63.

Math practice for Compensation Strategy

Add within 100 without regrouping

Practice this

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